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| Answers |
| 1. di = 22.5cm; hi = -2.5cm (1 / f) = (1 / do) + (1 / di) where f = 15 and do = 45; (hi / ho) = - (di / do) where ho = 5, do = 45, and di = 22.5 2. di = 19.2cm; real image (1 / f) = (1 / do ) + (1 / di) where f = 12 and do = 32. All inverted images are real images. 3. di = -8.1cm (1 / f) = (1 / do) + (1 / di) where f = -10.8 and do = 32.7. Substitute and solve for di. 4. di = -8.1; hi = 0.909cm (1 / f) = (1 / do) + (1 / di) where f = -12 and do = 25. Substitute and solve for di. (hi / ho) = - (di / do) where ho = 2.8, do = 25, and di = -8.1. Substitute and solve for hi. 5. F (+ or -) Image (+ or -) Real or virtual? Magnification Inverted or upright? Concave (do < f) + - Virtual + Upright Concave (2f > do > f) + + Real + Inverted Concave (do > 2f) + + Real - Inverted Convex - - Virtual - Upright |